-14x-44-x^2-4=0

Solution for -14x-44-x^2-4=0 equation:

-14x-44-x^2-4=0

We add all the numbers together, and all the variables

-1x^2-14x-48=0

a = -1; b = -14; c = -48;
Δ = b2-4ac
Δ = -142-4·(-1)·(-48)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*-1}=\frac{12}{-2}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*-1}=\frac{16}{-2}
=-8
$